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About Sylvan Lake

Sylvan Lake is a city in Oakland County in the U.S. state of Michigan. A northern suburb of Detroit, Sylvan Lake is located roughly 26 miles (41.8 km) from downtown Detroit, and borders Pontiac to the east. As of the 2010 census, the city had a population of 1,720. With a land area of 0.51 square miles (1.32 km2), Sylvan Lake is the fourth-smallest city by land area in the state after Clarkston, Petersburg, and neighboring Keego Harbor. == Geography == According to the United States Census Bureau, the city has a total area of 0.82 square miles (2.12 km2), of which 0.51 square miles (1.32 km2) is land and 0.31 square miles (0.80 km2) (37.8%) is water. == Demographics == === 2010 census === As of the census of 2010, there were 1,720 people, 809 households, and 474 families living in the city. The population density was 3,372.5 inhabitants per square mile (1,302.1/km2). There were 864 housing units at an average density of 1,694.1 per square mile (654.1/km2). The racial makeup of the city was 94.5% White, 2.2% African American, 0.3% Native American, 0.7% Asian, 0.5% from other races, and 1.7% from two or more races. Hispanic or Latino of any race were 1.5% of the population.